Print Each Character No of Times Based on Next Occurrence of Numeric Value in a given String using Java Program Eg 1: Input: a1b10 Output: abbbbbbbbbb

Write a program to give the following output for the given input

Eg 1: Input: a1b10
       Output: abbbbbbbbbb
Eg: 2: Input: b3c6d15
          Output: bbbccccccddddddddddddddd
The number varies from 1 to 99.

Program in JAVA:

public class PrintString {

 public static void main(String[] args) {
  
  String n="a10b5c03";
  char []a;
  char charValue = 0;
  int i,j,count=0,numberValue=0;
  a=n.toCharArray();
  for(i=0;i<a.length;i++) {
   
   if(Character.isDigit(a[i]))
   {
    while(Character.isDigit(a[i]))
    {
     numberValue=Character.getNumericValue(a[i]);
     count=(count*10)+numberValue;
     i++;
     if(i>(a.length-1))
     {
      i--;
      break;
     }
     
    }
    while(Character.isAlphabetic(a[i]))
    {
     i--;
     break;
    }
    
    for(j=0;j<count;j++) {
     System.out.print(charValue+" ");
    }
    count=0;
   }
   else
   {
    charValue=a[i];
   }
    
  }
 }

}

Output: